4x^2-68x+240=0

Solution for 4x^2-68x+240=0 equation:

4x^2-68x+240=0

a = 4; b = -68; c = +240;
Δ = b2-4ac
Δ = -682-4·4·240
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-28}{2*4}=\frac{40}{8}
=5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+28}{2*4}=\frac{96}{8}
=12
$